3[2+W]-W=4+2[W+1]

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Solution for 3[2+W]-W=4+2[W+1] equation:


Simplifying
3[2 + W] + -1W = 4 + 2[W + 1]
[2 * 3 + W * 3] + -1W = 4 + 2[W + 1]
[6 + 3W] + -1W = 4 + 2[W + 1]

Combine like terms: 3W + -1W = 2W
6 + 2W = 4 + 2[W + 1]

Reorder the terms:
6 + 2W = 4 + 2[1 + W]
6 + 2W = 4 + [1 * 2 + W * 2]
6 + 2W = 4 + [2 + 2W]

Combine like terms: 4 + 2 = 6
6 + 2W = 6 + 2W

Add '-6' to each side of the equation.
6 + -6 + 2W = 6 + -6 + 2W

Combine like terms: 6 + -6 = 0
0 + 2W = 6 + -6 + 2W
2W = 6 + -6 + 2W

Combine like terms: 6 + -6 = 0
2W = 0 + 2W
2W = 2W

Add '-2W' to each side of the equation.
2W + -2W = 2W + -2W

Combine like terms: 2W + -2W = 0
0 = 2W + -2W

Combine like terms: 2W + -2W = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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